7a^2+4=11a

Solution for 7a^2+4=11a equation:

7a^2+4=11a

We move all terms to the left:

7a^2+4-(11a)=0

a = 7; b = -11; c = +4;
Δ = b2-4ac
Δ = -112-4·7·4
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-3}{2*7}=\frac{8}{14}
=4/7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+3}{2*7}=\frac{14}{14}
=1
$